Question

-8x⁵y×(-0.4)x²y³ сколько будет срочно?

Answer 1

Ответ:

-8x^5y*(-0.4)x²y³

8x^5y*0,4x²y³

3,2x^5yx²y³

$3.2 {x}^{5 + 2} {y}^{1} \times y ^{3}$

$3.2x ^{7} {y}^{1 + 3}$

$3.2 {x}^{7} {y}^{4}$

Answer 2

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