Question

помоги плиссс<33333 ​

Answer 1

Ответ:

$\displaystyle arccos \frac{ \sqrt{3} }{2} - arctg1 + arcsin \bigg( - \frac{ \sqrt{2} }{2} \bigg) =$

$\displaystyle = \frac{\stackrel{2/}{}\pi}{6} - \frac{\stackrel{3/}{}\pi}{4} - \frac{\stackrel{3/}{}\pi}{4} = - \frac{ \stackrel{1/}{}\not4\pi}{ \stackrel{3/}{}\not12} = \bf - \frac{\pi}{3}$

Ответ: π/3