Question

2x^2-4xy^2+3xy-6y^3 при x=1//4 y=1//6

Answer 1

$2x^2-4xy^2+3xy-6y^3 = 2x(x-2y^2)+3y(x-2y^2) = (x-2y^2)(2x+3y)$

x = 1/4

y = 1/6

 $(x-2y^2)(2x+3y) = (frac{1}{4}-2frac{1}{36})(2frac{1}{4}+3frac{1}{6}) = frac{7}{36}$