Предмет: Математика, автор: isaevaaazan26

log₂ x = 3; log x= -1 -1; log (2x + 1) = 6; log, (x² + x - 5) = -1; 7 log₂ (3x - 6) = log₂ (2x - 3); logo,2 (12x+ 8) = logo,2 (11x + 7). lg (x²8) lg (2 - 9x); log₂x = log₂ 3 + log₂ 5;

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Ответы

Автор ответа: ars3736

Ответ:

крч казак тили бжб керек Жахандык маселелер

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log₂ x = 3; log x= -1 -1; log (2x + 1) = 6; log, (x² + x - 5) = -1; 7 log₂ (3x - 6) = log₂ (2x - 3); logo,2 (12x+ 8) = logo,2 (11x + 7). lg (x²8) lg (2 - 9x); log₂x = log₂ 3 + log₂ 5;​

Ответы

log₂ x = 3; log x= -1 -1; log (2x + 1) = 6; log, (x² + x - 5) = -1; 7 log₂ (3x - 6) = log₂ (2x - 3); logo,2 (12x+ 8) = logo,2 (11x + 7). lg (x²8) lg (2 - 9x); log₂x = log₂ 3 + log₂ 5;