Предмет: Физика, автор: starlodroid

Автомобіль рухається по горизонтальній ділянці шляху зі швидкістю 20м/с.
Визначити мінімальний час руху автомобіля до повної зупинки при
гальмуванні, якщо коефіцієнт тертя колес об дорогу складає 0,4.

Ответы

Автор ответа: tomwxw
1

Ответ:

VO = 20 M/C.

V = 0 м/c.

g = 10 м/с². u = 0,4.

t-?

Время торможения t выразим из

движения: t = (VO - V)/a.

с.

формулы для ускорения Так как автомобиль остановился, то его конечная скорость V = 0 м/

Формула примет вид: t = VO/a.

Запишем 2 закон Ньютона при торможении автомобиля: м *a =

FTP.

Ftp = u *m*g. m *a = μ *m *g.

a =m*g.

Формула для определения

времени торможения примет вид:

t=VO/u *g.

t = 20 m/c/0,4 *10 м/с2= 5 с.

Ответ: минимальное время движения автомобиля до полной

tomwxw: можете сделать лучшим ответом пожалуйста прошу очень надо
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