Question

пжпжпжпжжппж будь ласка ​

Answer 1

Ответ:

Объяснение:

(2y)/(y+3) +(y-3)²·(2/(9-6y+y²) +1/(9-y²))=3

(2y)/(y+3) +(y-3)²·(2/(y-3)² -1/((y-3)(y+3)))=3

(2y)/(y+3) +(y-3)²·(2y+6-y+3)/((y-3)²(y+3))=3

(2y)/(y+3) +(y+9)/(y+3)=3

(2y+y+9)/(y+9)=3

(3y+9)/(y+3)=3

(3(y+3))/(y+3)=3

3=3