Question

0673. a) (5√√2-√18 ). √2 ;
6) (3√5-2√/20).
√5;
B)(√50-2√2). √√2;
r) (4√3+ √27)-√3.
0674. a)(√20-2√3+ √5). √5;
6) (3√5 - √6 +1)·2√2;
B) (2√3+√15-√10). √5;
r) (4√3-2√6-1)-2√3.

Answer 1

Ответ:

$(5 \sqrt{2} - \sqrt{18} ) \times \sqrt{2} \\ (5 \sqrt{2} - 3 \sqrt{2} ) \sqrt{2} \\ 2 \sqrt{2} \sqrt{2} \\ 2 \times 2 \\ 4$

$(3 \sqrt{5} - 2 \sqrt{20} ) \times \sqrt{5} \\ (3 \sqrt{5} - 4 \sqrt{5} ) \sqrt{5} \\ - \sqrt{5} \times \sqrt{5} \\ - 5$

$(50 - 2 \sqrt{2} ) \times \sqrt{2} \\ (5 \sqrt{2} - 2 \sqrt{2} ) \sqrt{2} \\ 3 \sqrt{2} \sqrt{2} \\ 3 \times 2 \\ 6$

$(4 \sqrt{3} + \sqrt{27} ) \times \sqrt{3} \\ (4 \sqrt{3} + 3 \sqrt{3} ) \sqrt{3} \\ 7 \sqrt{3} \sqrt{3} \\ 7 \times 3 \\ 21$