Question

нужно срочно решить , прошу загрузите фото с решением ​

Answer 1

$\frac{x - 1}{3x - 12} - \frac{x - 3}{2x - 8} = \frac{x - 1}{3(x - 4)} - \frac{x - 3}{2(x - 4)} = \frac{2x - 2 - 3x + 9}{6(x - 4)} = \frac{7 - x}{6x - 24}$

$\frac{8x}{ {x}^{2} - 16 } - \frac{4}{x + 4} = \frac{8x - 4(x - 4)}{(x - 4)(x + 4)} = \frac{8x - 4x - 16}{ {x}^{2} - 16} = \frac{4x - 16}{ {x}^{2} - 16 } = \frac{4(x - 4)}{(x - 4)(x + 4)} = \frac{4}{x + 4}$

$\frac{3}{a + 1} + \frac{a + 4}{ {a}^{2} + a } = \frac{3a + a + 4}{a(a + 1)} = \frac{4a + 4}{a(a + 1)} = \frac{4(a + 1)}{a(a + 1)} = \frac{4}{a}$

$\frac{a - b}{4a - 4b} + \frac{a + b}{4b - 4a} = \frac{a - b}{4(a - b)} + \frac{a + b}{4(b - a)} = \frac{1}{4} + \frac{a + b}{4(b - a)} = \frac{b - a + a + b}{4(b - a)} = \frac{2b}{4(b - a)} = \frac{b}{2b - 2a}$

$\frac{ {b}^{2} }{by - {y}^{2} } + \frac{b}{y - b} = \frac{ {b}^{2} }{y(b - y)} - \frac{b}{b - y} = \frac{ {b}^{2} - by }{y(b - y)} = \frac{b(b - y)}{y(b - y)} = \frac{b}{y}$