Question

1 пример!
$frac{3}{x+2}- frac{3}{2-x} = frac{2}{ x^{2}-4 }$

Answer 1

$frac{3}{x+2}-frac{3}{2-x}=frac{2}{x^2-4}$
$x+2 neq 0;x-2 neq 0$
$x neq ^+_-2$
$frac{3}{x+2}+frac{3}{x-2}=frac{2}{(x-2)(x+2)}$
$3(x-2)+3(x+2)=2$
$3x-6+3x+6=2$
$6x=2$
$3x=1$
$x=frac{1}{3}$
отвте: 1/3