Question

помогите ,даю 100 баллов

Answer 1

Ответ:

решение смотри на фотографии

Answer 2

Первая фотография:

$a) \: \: \: \: \: \frac{24 {}^{ - 3} }{ {8}^{ - 3} } = \frac{ {8}^{ - 3} \times {3}^{ - 3} }{ {8}^{ - 3} } = {3}^{ - 3} = {( \frac{1}{3} )}^{3} = \frac{1}{9}$

$б) \: \: \: \: \: \frac{6.5 {}^{ - 5} }{ {13}^{ - 5} } = \frac{ {6.5}^{ - 5} \times {2}^{ - 5} }{ {6.5}^{ - 5} } = {2}^{ - 5} = {( \frac{1}{2} )}^{5} = \frac{1}{32}$

$в) \: \: \: \: \: {2}^{ - 5} \times {5}^{ - 5} = {10}^{ - 5} = ( \frac{1}{10} {)}^{5} = \frac{1}{100000}$

$г) \: \: \: \: \: {3}^{ - 8} \times ( \frac{1}{3} ) {}^{ - 8} = 1$

$д) \: \: \: \: \: {0.125}^{ - 10} \times {8}^{ - 10} = {1}^{ - 10} = 1$

$е) \: \: \: \: \: {0.2}^{ - 6} \times {0.5}^{ - 6} = {0.1}^{ - 6} = {( \frac{1}{10} )}^{ - 6} = {10}^{6} = 1000000$

Вторая фотография:

$a) \: \: \: \: \: {3}^{7} \times {3}^{ - 5} = {3}^{2} = 9$

$б) \: \: \: \: \: {2}^{ - 8} \times {2}^{5} = {2}^{ - 3} = {( \frac{1}{2} )}^{3} = \frac{1}{8}$

$в) \: \: \: \: \: 49 \times {7}^{ - 3} = {7}^{2} \times {7}^{ - 3} = {7}^{ - 1} = \frac{1}{7}$

$г) \: \: \: \: \: 3 \div {3}^{ - 3} = {3}^{ - 4} = {( \frac{1}{3}) }^{4} = \frac{1}{81}$

$д) \: \: \: \: \: 16 \div {2}^{ - 3} = {2}^{4} \div {2}^{ - 3} = {2}^{7} = 128$

$e) \: \: \: \: \: {10}^{ - 6} \div {10}^{ - 4} \div {10}^{ - 8} = {10}^{ - 2} \div {10}^{ - 8} = {10}^{6} = 1000000$

$ж) \: \: \: \: \: { {(5}^{ - 3}) }^{ - 1} = {5}^{3} = 125$

$з) \: \: \: \: \: (( { { \frac{1}{7} }^{ - 1} )}^{2} = {( \frac{1}{7} )}^{ - 2} = {7}^{2} = 49$

$и) \: \: \: \: \: { {(0.01}^{ - 2} })^{ - 1} = ( {0.01)}^{2} = 0.0001$

$к) \: \: \: \: \: { {(3}^{ - 2} )}^{ - 2} \times {3}^{ - 4} = {3}^{4} \times {3}^{ - 4} = 1$

$л) \: \: \: \: \: {25}^{ - 4} \div {5}^{ - 7} = { {(5}^{2}) }^{ - 4} \div {5}^{ - 7} = {5}^{ - 8} \div {5}^{ - 7} = {5}^{ - 1} = \frac{1}{5} = 0.2$

$м) \: \: \: \: \: {6}^{ - 1} \times {( {6}^{ - 4}) }^{3} \div {36}^{ - 7} = {6}^{ - 1} \times {6}^{ - 12} \div { {(6}^{2}) }^{ - 7} = {6}^{12} \div {6}^{ - 14} = {6}^{26}$

Третья фотография:

$a) \: \: \: \: \: {3}^{9} \div {3}^{6} = {3}^{3} = 27$

$б) \: \: \: \: \: ( \frac{1}{4} ) {}^{10} \div {(0.25)}^{8} = {0.25}^{10} \div {0.25}^{8} = {0.25}^{2} = 0.0625$

$в) \: \: \: \: \: ( { - 2.35)}^{15} \div {( - 2.35)}^{14} = - 2.35$

$г) \: \: \: \: \: {0.2}^{13} \div {0.2}^{11} = {0.2}^{2} = 0.04$

$д) \: \: \: \: \: {(2 \frac{1}{7} )}^{11} \div {(2 \frac{1}{7}) }^{9} = {(2 \frac{1}{7}) }^{2} = (\frac{15}{7} {)}^{2} = \frac{225}{49} = 4 \frac{29}{49}$

$e) \: \: \: \: \: ( {0.5)}^{9} \div {( \frac{1}{2} )}^{5} = {0.5}^{9} \div {0.5}^{5} = {0.5}^{4} = 0.0625$