Question

допоможіть будь ласка ​

Answer 1

${6}^{x + 1} = {3}^{x + 1} \\ {( {3}^{2} )}^{x + 1} = {3}^{x + 1} \\ {3}^{2(x + 1)} = {3}^{x + 1} \\ {3}^{2x + 2} = {3}^{x + 1} \\ 2x + 2 = x + 1 \\ 2x - x = 1 - 2 \\ x = - 1$

${2}^{x - 5} = {8}^{x - 5} \\ {2}^{x - 5} = { ({2}^{3} )}^{x - 5} \\ {2}^{x - 5} = {2}^{3(x - 5)} \\ {2}^{x - 5} = {2}^{3x - 15} \\ x - 5 = 3x - 15 \\ x - 3x = - 15 + 5 \\ - 2x = - 10 \\ x = 5$