Question

 x²+$frac{5}{6}$Χ+$frac{1}{6}$=0

Answer 1

$x^2+frac{5}{6}x+frac{1}{6}=0$
$6x^2+5x+1=0$
$(2x+1)(3x+1)=0$
$2x+1=0;x_1=-frac{1}{2}$
$3x+1=0;x_2=-frac{1}{3}$