Question

1) 18(а-2) =12а-(20-(6а–16))) 2) 2(х-y+t)-3(x+y-t)-5(t-y)=-x
Помогите даю 100 балов!!!​

Answer 1

Ответ:

$1)18(a - 2) = 12a -( 20 - (6a - 16)) \\ 18a - 36 = 12a -( 20 - 6a + 16) \\ 18a - 36 = 12a - 36 + 6a \\ 18a - 36 = 18a - 36$

$2)2( x - y + t) - 3(x + y - t) - 5(t - y) = - x \\ 2x - 2y + 2t - 3x - 3y + 3t - 5t + 5y = - x \\ - x = - x$