Question

Хотябы басын комектесіңдерш пж пжп пжпп жпжп ​

Answer 1

$\displaystyle\bf\\1)\\\\arcCos\Big(-\frac{\sqrt{2} }{2} \Big)+arcSin\Big(-0,5\Big)=\frac{3\pi }{4}-\frac{\pi }{6} =\frac{9\pi -2\pi }{12} =\frac{7\pi }{12} \\\\3)\\\\arcCos \ 0,5+arcSin(-1)=\frac{\pi }{3} -\frac{\pi }{2} =\frac{2\pi -3\pi }{6} =-\frac{\pi }{6} \\\\1)\\\\arcCtg(-1)-arctg\sqrt{3} =\frac{3\pi }{4} -\frac{\pi }{3} =\frac{9\pi -4\pi }{12} =\frac{5\pi }{12} \\\\3)$

$\displaystyle\bf\\arcCtg\Big(-\frac{\sqrt{3} }{3} \Big)+arcCtg(-\sqrt{3} )=\frac{2\pi }{3} +\frac{5\pi }{6} =\frac{4\pi +5\pi }{6} =\frac{9\pi }{6} =\frac{3\pi }{2}$