Question

якщо х=14 , помогите​

Answer 1

$\displaystyle\bf\\\frac{x^{2} }{4x-8} +\frac{4}{8-4x} =\frac{x^{2} }{4x-8} -\frac{4}{4x-8} =\frac{x^{2} -4}{4x-8} =\\\\\\=\frac{(x-2)\cdot(x+2)}{4\cdot(x-2)} =\frac{x+2}{4} \\\\\\x=14\\\\\\\frac{x+2}{4} =\frac{14+4}{4} =\frac{18}{4} =4,5\\\\\\Otvet \ : \ 4,5$