Question

. ПОМОГИТЕ, ДАЮ 30 БАЛОВ​

Answer 1

$\displaystyle\bf\\\frac{b^{2} -6a^{2} }{3a+b} +3a-b=\frac{b^{2} -6a^{2} +(3a+b)\cdot(3a-b)}{3a+b} =\\\\\\=\frac{b^{2} -6a^{2} +9a^{2} -b^{2} }{3a+b}=\frac{3a^{2} }{3a+b}$

Answer 2

$\frac{3a^{2} }{3a+b}$