Question

(x ^ 2 - 8x)/(8x - 8), якщо х=0,6

Answer 1

Решение и ответ:

$\displaystyle \frac{{{x^2}-8x}}{{8x-8}} = \frac{{x\left( {x-8} \right)}}{{8\left( {x-1} \right)}} = \frac{{0.6\left( {0.6-8} \right)}}{{8\left( {0.6-1} \right)}} = \frac{{0.6\left( {0.6-8} \right)}}{{8\left( {0.6-1} \right)}} = \frac{{0.6 \cdot \left({-7.4} \right)}}{{8\left({-0.4} \right)}} = \frac{{-4.44}}{{-3.2}}=1.3875$