Question

30 БАЛЛОВ, ПОМОГИТЕ ПЖ!

Answer 1

$\displaystyle\bf\\1)\\\\\frac{4x}{x-12} =\frac{4x\cdot(x+12)}{(x-12)\cdot(x+12)}=\frac{4x^{2} +48x}{x^{2} -144} \\\\\\2)\\\\\frac{8y}{x+12} =\frac{8y\cdot(x-12)}{(x+12)\cdot(x-12)} =\frac{8yx-96y}{x^{2} -144}$

Ответ под номером 5 .