Question

7/9b^2-9/28=0 найдите корень уравнения

Answer 1

Ответ:

$b_1 = \dfrac{9}{14}\\b_2 = -\dfrac{9}{14}$

Объяснение:

$\dfrac{7}{9}b^2-\dfrac{9}{28} = 0$

$\dfrac{7}{9}b^2=\dfrac{9}{28}$

$b^2=\dfrac{9}{28} \div\dfrac{7}{9}$

$b^2=\dfrac{9}{28} \cdot\dfrac{9}{7}$

$b=\pm\sqrt{\dfrac{9\cdot 9}{4\cdot 7 \cdot7}} = \pm\dfrac{9}{2 \cdot 7}= \pm\dfrac{9}{14}$

$b_1 = \dfrac{9}{14}$

$b_2 = -\dfrac{9}{14}$