Question

Помогите пожалуйста!:
к) 3 1/2×(2/3x+4/7)=2 1/3;
л) (5/8x-1/5)×3/4=3/4;
м) 3/5z+2/3z-3=4/5.
(Если что, это выражения с дробями).​

Answer 1

Пошаговое объяснение:

К)

3 1/2 * (2/3х + 4/7) = 2 1/3

2/3х + 4/7 = 2 1/3 : 3 1/2

2/3х + 4/7 = 7/3 : 7/2

2/3х + 4/7 = 7/3 * 2/7

2/3х + 4/7 = 2/3

2/3х = 2/3 - 4/7

2/3х = 14/21 - 12/21

2/3х = 2/21

х = 2/21 : 2/3

х =2/21 * 3/2

х = 3/21

х = 1/7

Л)

(5/8х - 1/5) * 3/4 = 3/4

5/8х - 1/5 = 3/4 : 3/4

5/8х - 1/5 = 1

5/8х = 1 + 1/5

5/8х = 1 1/5

5/8х = 6/5

х = 6/5 : 5/8

х = 6/5 * 8/5

х = 48/25

х = 1 23/25

М)

3/5z + 2/3z - 3 = 4/5

9/15z + 10/15z - 3 = 4/5

9/15z + 10/15z = 4/5 + 3

19/15z = 3 4/5

19/15z = 19/5

z = 19/5 : 19/15

z = 19/5 * 15/19

z = 15/5

z = 3