Question

ДАЮ 50 БАЛЛОВ!
ДАЮ 50 БАЛЛОВ!

Answer 1

$\displaystyle\bf\\1)\\\\\frac{1+2x}{2} -\frac{3x+2}{3} =\frac{5x+4}{6} \\\\\\\frac{1+2x}{2}\cdot 6-\frac{3x+2}{3}\cdot 6 =\frac{5x+4}{6} \cdot 6\\\\\\3\cdot(1+2x)-2\cdot(3x+2)=5x+4\\\\3+6x-6x-4=5x+4\\\\5x=3-4-4\\\\5x=-5\\\\\boxed{x=-1}\\\\\\2)\\\\\frac{1+3x}{5} -\frac{2+x}{2} =\frac{x-8}{10} \\\\\\\frac{1+3x}{5} \cdot 10-\frac{2+x}{2} \cdot 10=\frac{x-8}{10} \cdot 10\\\\\\2\cdot(1+3x)-5\cdot(2+x)=x-8\\\\2+6x-10-5x=x-8\\\\6x-5x-x=-8-2+10\\\\0\cdot x=0\\\\\boxed{x\in R}$

$\displaystyle\bf\\3)\\\\5y(5y-2)=(5y-1)(5y+1)\\\\25y^{2} -10y=25y^{2} -1\\\\-10y=-1\\\\\boxed{y=0,1}$