Question

помогииииттеее срооочно​

Answer 1

Ответ:

Объяснение:

1) $\frac{a}{4a+b}$ = $\frac{3a}{3(4a+b)}$ = $\frac{3a}{12a+3b}$

2)$\frac{1}{x-4y}$ = $\frac{1*(x+4y)}{(x-4y)(x+4y)}$ = $\frac{x+4y}{x^{2} -16y^{2} }$

3) $\frac{2x}{5x+y}$ = $\frac{2x(5x+y)}{(5x+y)(5x+y)}$ = $\frac{2x(5x+y)}{(5x+y)^{2} }$ = $\frac{10x^{2} +2xy}{25x^{2} +2*5xy+y^{2} }$ = $\frac{10x^{2} +2xy}{25x^{2} +10xy+y^{2} }$

4) $\frac{4b}{2-3b}$ = $\frac{4b(2-3b)}{(2-3b)(2-3b)}$ = $\frac{4b(2-3b)}{(2-3b)^{2} }$ = $\frac{8b-12b^{2} }{4-2*2*3b+9b^{2} }$ = $\frac{8b-12b^{2} }{4-12b+9b^{2} }$