Question

X²-9=y³+42
Найти вторую переменную, если
y=12
y=4
x=9
x=4,6
x=32
​

Answer 1

${x}^{2} - 9 = {y}^{3} + 42$

${x}^{2} - 9 = {12}^{3} + 42 \\ {x}^{2} - 9 = 1728 + 42 \\ {x}^{2} - 9 = 1770 \\ {x}^{2} = 1770 + 9 \\ {x}^{2} = 1779 \\ x = ± \sqrt{1779}$

${x}^{2} - 9 = {4}^{3} + 42 \\ {x}^{2} - 9 = 64 + 42 \\ {x}^{2} - 9 = 106 \\ {x}^{2} = 106 + 9 \\ {x}^{2} = 115 \\ {x}^{} = ± \sqrt{115}$

${x}^{2} - 9 = {9}^{3} + 42 \\ {x}^{2} - 9 = 729 + 42 \\ {x}^{2} - 9 = 771 \\ {x}^{2} = 771 + 9 \\ {x}^{2} = 780 \\ x = ± \sqrt{780}$

${x}^{2} - 9 = {4.6}^{3} + 42 \\ {x}^{2} - 9 = 97,336 + 42 \\ {x}^{2} - 9 = 139.336 \\ {x}^{2} = 139.336 + 9 \\ {x}^{2} = 148.336 \\ x = ± \sqrt{148.336}$

${x}^{2} - 9 = {32}^{3} + 42 \\ {x}^{2} - 9 = 32 768 + 42 \\ {x}^{2} - 9 = 32810 \\ {x}^{2} = 32810 + 9 \\ {x}^{2} = 32819 \\ x = ± \sqrt{32819}$