Question

Помогите пожалуйста!!​

Answer 1

a²-3a

a = 5

5² - 3 * 5 = 25 - 15 = 10

a = 0

0² - 3*0 = 0

a = 1

1² - 3*1 = 1 - 3 = -2

b) 3$\frac{1}{4}$ + 2$\frac{1}{6}$ : 2$\frac{3}{5}$ - $\frac{2}{3}$ : $\frac{4}{9}$

$3\frac{1}{4} + 2\frac{1}{6} * 2\frac{5}{3} - \frac{2}{3}* \frac{9}{4} = 3\frac{1}{4} + \frac{65}{9} - \frac{3}{2} = \frac{13}{4} + \frac{65}{9} - \frac{3}{2} = \frac{117 + 260 - 54}{36} = \frac{323}{36} = 8\frac{35}{36}$

Answer 2

Объяснение:

а²-3а=а(а-3)

а=5 ; 5(5-3)=5×2=10

а=0; 0(0-3)=0

а=1 ; 1(1-3)=1×(-2)= -2

3 1/4+2 1/6:2 3/5-2/3:4/9=2 7/12

1) 2 1/6:2 3/5=13/6:13/5=13/6×5/13=5/6

2) 2/3:4/9=2/3×9/4=1/1×3/2=3/2=1 1/2

3) 3 1/4+5/6=3 3/12+10/12=3 13/12=

=3+1 1/12=4 1/12

4) 4 1/12-1 1/2= (4-1)+(1/12-6/12)=

=3+(-5/12)=3-5/12=2 12/12-5/12= 2 7/12