Question

(x²-2x-1)(x²-2x-3)=0​

Answer 1

Пошаговое объяснение:

$(x ^{2} - 2x - 1)(x ^{2} - 2x - 3) = 0 \\ x ^{2} - 2x - 1 = 0 \\ x ^{2} - 2x - 3 = 0 \\ x = 1 + \sqrt{2} \\ x = 1 - \sqrt{2} \\ x = - 1 \\ x = 3 \\ x1 = - 1 \\ x2 = 1 - \sqrt{2} \\ x3 = 1 + \sqrt{2} \\ x4 = 3$