Question

Помогите со вторым пожалуйста

Answer 1

Cr2O3

Mr(Cr2O3) = 2 × 52 + 3 × 16 = 152

w(Cr) = 2 × 52 / 152 × 100% = 68%

w(O) = 3 × 16 / 152 × 100% = 32%

Al(OH)3

Mr(Al(OH)3) = 1 × 27 + 3 × 16 + 3 × 1 = 78

w(Al) = 1 × 27 / 78 × 100% = 35%

w(O) = 3 × 16 / 78 × 100% = 61%

w(H) = 3 × 1 / 78 × 100% = 4%