Предмет: Математика, автор: iradzivoronuk

Периметр рівнобедреного трикутника дорівнює 17 см, а його основа - 5 см. Знайдіть бічну сторону трикутника.

Написати розв'язок і повну відповідь, будь ласка

Ответы

Автор ответа: 000wrabbit

1

Ответ:

Пошаговое объяснение:

Дано: Δ АВС- рівнобедрений

АС=5 см, РΔАВС=17 см

Знайти АВ-?

Розв'язання:

т.к ΔАВС - рівнобедрений (за умовою), то АВ=ВС (як бічні сторони рівнобедреного треугольника)

РΔАВС= АВ+ВС+АС ⇒АВ=ВС=( РΔАВС -АС):2=(17-5):2=12:2=6 см.

Відповідь: бічні сторони дорівнюють АВ=ВС=6 см

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