Question

|-5/18|×|-3/10|+7/12 және |25/26|×|26/75|·|-1|;​

Answer 1

Решение и ответ:

$\displaystyle \left|{-\frac{5}{{18}}}\right|\cdot\left|{-\frac{3}{{10}}}\right|+\frac{7}{{12}}=\boxed{\frac{2}{3}}$

$\displaystyle 1)\;\;\left|{-\frac{5}{{18}}}\right|\cdot\left|{-\frac{3}{{10}}}\right|=\frac{5}{{18}}\cdot\frac{3}{{10}}=\frac{\textbf{5}}{{6\cdot \textbf{3}}}\cdot \frac {\textbf{3}}{{\textbf{5}\cdot 2}}=\frac{1}{6}\cdot\frac{1}{2}=\frac{1}{{12}}$

$\displaystyle 2)\;\;\frac{1}{{12}}+\frac{7}{{12}}=\frac{{1+7}}{{12}}=\frac{8}{{12}}=\frac{{\textbf{4}\cdot 2}}{{\textbf{4}\cdot 3}}=\frac{2}{3}$

$\displaystyle \left|{\frac{{25}}{{26}}}\right|\cdot\left|{\frac{{26}}{{75}}}\right|\cdot\left|{-1}\right|=\boxed{\frac{1}{3}}$

$\displaystyle 1)\;\;\left|{\frac{{25}}{{26}}}\right|\cdot\left|{\frac{{26}}{{75}}}\right|=\frac{{25}}{{26}}\cdot\frac{{26}}{{75}}=\frac{{\textbf{25}}}{{\textbf{26}}}\cdot\frac{{\textbf{26}}}{\textbf{25}\cdot 3}}=\frac{1}{3}$

$\displaystyle 2)\;\;\frac{1}{3}\cdot\left|{-1}\right|=\frac{1}{3}\cdot 1=\frac{1}{3}$