Question

x²+6x-2=0 .............​

Answer 1

Ответ: ↓

${x}^{2} + 6x - 2 = 0 \\ D = {6}^{2} - 4 \times 1 \times ( - 2) = 36 + 8 = 44 \\ x1x2 = \frac{ - 6± \sqrt{44} }{2 \times 1} \\ x1x2 = \frac{ - 6 - \sqrt{44} }{2} \: ; \: \frac{ - 6 + \sqrt{44} }{2}$