Question

(4х²-3х-7)-(2х²-3х+1) пжжж срочно

Answer 1

Ответ:

$(4x ^{2} - 3 x - 7) - (2x ^{2} - 3x + 1) \\ 4 x^{2} - 3x - 7 - (2x ^{2} - 3x + 1) \\ 4x ^{2} - 3x - 7 - 2x ^{2} + 3x - 1 \\ 4x ^{2} - 7 - 2x ^{2} - 1 \\ 2 x^{2} - 7 - 1 \\ 2x ^{2} - 8$