Question

4) 4,6-(x-3)>4, 2+x;​

Answer 1

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$\displaystyle \bf 4.6-\left(x-3\right) > 4.2+x\\\\4.6-x+3 > 4.2+x\\\\4.6+3-4.2 > x+x\\\\3.4 > 2x\\\\x < \frac{3.4}{2} \\\\x < 1.7$

$\boxed { \Big \displaystyle \bf x \in \Big(- \infty \ ; \ 1.7\Big)}$