Question

2) x ^ 3 + 4x ^ 2 - 4x - 16 = 0

1) 9x ^ 3 + 12x ^ 2 + 4x = 0

4. Розв'яжіть рівняння:

Answer 1

$1){x}^{2} (x + 4) - 4x - 16 = 0$

${x}^{2} (x + 4) - 4(x + 4) = 0$

$(x + 4)( {x}^{2} - 4) = 0$

$x + 4 = 0$

${x}^{2} - 4 = 0$

$x = - 4$

$x = - 2$

$x = 2$

$x1 = - 4$

$x2 = - 2$

$x3 = 2$

$2)x(9 {x}^{2} + 12x + 4) = 0$

$x(3x + 2) {}^{2} = 0$

$x = 0$

$(3x + 2 {)}^{2} = 0$

$x = 0$

$x = - \frac{2}{3}$

$x1 = - \frac{2}{3}$

$x2 = 0$