Question

помогите пожалуйста ​

Answer 1

$\displaystyle\mathsf{f(x)=-3x^2+2x}\\\displaystyle\mathsf{f(1)=-3*(1)^2+2*(1)=-1.}\\\displaystyle\mathsf{f(0)=-3*(0)^2+2*(0)=0.}\\\displaystyle\mathsf{f(1/3)=-3*(1/3)^2+2*(1/3)=1/3.}\\\displaystyle\mathsf{f(-2)=-3*(-2)^2+2*(-2)=-16.}$