Question

(2х+1 - 1/ 1-2х)/( 2х -4х2/ 2х-1)

Answer 1

$\displaystyle\bf\\\Big(2x+1-\frac{1}{1-2x} \Big):\Big(2x-\frac{4x^{2} }{2x-1} \Big)=\frac{(2x+1)\cdot(1-2x)-1}{1-2x} :\frac{2x\cdot(2x-1)-4x^{2} }{2x-1} =\\\\\\=\frac{1-4x^{2} -1}{1-2x} :\frac{4x^{2} -2x-4x^{2} }{2x-1} =\frac{-4x^{2} }{1-2x}:\frac{-2x}{2x-1} =-\frac{4x^{2} }{1-2x} \cdot\frac{1-2x}{2x} =\\\\\\=-\frac{4x^{2} }{2x} =-2x$