Предмет: Химия, автор: tolia77

Дано Густота(CxHy) = 2,59 г/моль
Карбон 82,76 процентів
Гідроген 17,24 проценти.
Знайти: молекулярну формулу

Ответы

Автор ответа: MasterBivin
0

Думаю там не г/моль, а г/дм3, ведь это плотность.

Находим молярную массу CxHy.

p = M/Vm --> p*Vm = M

2,59 г/дм3 * 22,4дм3/моль ≈ 58г/моль

Теперь ищем сколько атомов чего было.

58г/моль * 82,76% ≈ 48г/моль

          100%

58г/моль * 17,24% ≈ 10г/моль

          100%

кол. атомов углерода = 48г/моль / 12г/моль = 4

кол. атомов водорода = 10г/моль / 1г/моль =  10

Формула: C4H10 - бутан

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