Question

помогите решить дам 30б​

Answer 1

Решение.

Сначала вычислим первую дробь, затем вторую и сложим результаты .

$\displaystyle \bf 1)\ \ \frac{9\dfrac{1}{2}:1,9-4\dfrac{1}{3}}{2,32\cdot \dfrac{15}{29}+\dfrac{4}{5}}=\frac{\dfrac{19}{2}:\dfrac{19}{10}-\dfrac{13}{3}}{\dfrac{232}{100}\cdot \dfrac{15}{29}+\dfrac{4}{5}}=\frac{\dfrac{19}{2}\cdot \dfrac{10}{19}-\dfrac{13}{3}}{\dfrac{58}{25}\cdot \dfrac{15}{29}+\dfrac{4}{5}}=\frac{5-\dfrac{13}{3}}{\dfrac{2}{5}\cdot \dfrac{3}{1}+\dfrac{4}{5}}=\\\\\\=\frac{\dfrac{15-13}{3}}{\dfrac{6+4}{5}}=\frac{\dfrac{2}{3}}{\dfrac{10}{5}}=\frac{2}{3\cdot 2}=\frac{1}{3}$

$\displaystyle \bf 2)\ \ \frac{\Big(6+7\dfrac{1}{2}\Big):15}{\Big(1\dfrac{7}{15}+\dfrac{1}{3}\Big)\cdot \dfrac{3}{4}}=\frac{\Big(6+\dfrac{15}{2}\Big):15}{\Big(\dfrac{22}{15}+\dfrac{1}{3}\Big)\cdot \dfrac{3}{4}}=\frac{\dfrac{12+15}{2}\cdot \dfrac{1}{15}}{\dfrac{22+5}{15}\cdot \dfrac{3}{4}}=\frac{\dfrac{27}{2\cdot 15}}{\dfrac{27}{5\cdot 4}}=\\\\\\=\frac{27\, \cdot \, 5\cdot 4}{2\cdot 15\, \cdot \, 27}=\frac{2}{3}$

$\bf 3)\ \ \ \ \dfrac{1}{3}+\dfrac{2}{3}=\dfrac{3}{3}=1$    

Ответ:    1   .  

Answer 2

Ответ:

$\displaystyle\frac{9\dfrac{1}{2}:1.9-4\dfrac{1}{3} }{2.23-\dfrac{15}{29}+\dfrac{4}{5} } +\frac{(6+7\dfrac{1}{2}):15 }{(1\dfrac{7}{15}+\dfrac{1}{3})*\dfrac{3}{4} } =1$

Пошаговое объяснение:

$1)\displaystyle9\frac{1}{2} :1.9=\frac{19}{2} :\frac{19}{10} =\frac{19}{2} *\frac{10}{19} =5$

$\displaystyle2)5-4\frac{1}{3} =4\frac{3}{3} -4\frac{1}{3} =\frac{2}{3}$

$3)\displaystyle2.32*\frac{15}{29} =\frac{232}{100} *\frac{15}{29} =\frac{58}{25} *\frac{15}{29} =\frac{2*15}{25} =\frac{30}{25} =\frac{6}{5}$

$4)\displaystyle\frac{6}{5} +\frac{4}{5} =\frac{10}{5} =2$

$5)\displaystyle\frac{2}{3} :2=\frac{2}{3} *\frac{1}{2} =\frac{1}{3}$

$6)\displaystyle6+7\frac{1}{2} =13\frac{1}{2}$

$\displaystyle7)13\frac{1}{2} :15=\frac{27}{2} *\frac{1}{15} =\frac{9}{10}$

$8)\displaystyle1\frac{7}{15} +\frac{1}{3} =\frac{22}{15} +\frac{1}{3} =\frac{22}{15} +\frac{5}{15} =\frac{27}{15} =\frac{9}{5}$

$9)\displaystyle\frac{9}{5} *\frac{3}{4} =\frac{27}{20}$

$10)\displaystyle\frac{9}{10} :\frac{27}{20} =\frac{9}{10} *\frac{20}{27} =\frac{2}{3}$

$11)\displaystyle\frac{1}{3} +\frac{2}{3} =\frac{3}{3} =1$