Question

Помогите с заданием пожалуйста

Answer 1

$\displaystyle\bf\\\frac{1}{x-7} +\frac{1}{x+4} =0\\\\\\\frac{x+4+x-7}{(x-7)(x+4)} =0\\\\\\\frac{2x-3}{(x-7)(x+4)} =0\\\\\\2x-3=0 \ \ \ , \ \ \ x-7\neq 0 \ \ \ ; \ \ \ x+4\neq 0\\\\\\2x=3 \ \ \ ; \ \ \ x\neq 7 \ \ \ ; \ \ \ x\neq -4\\\\\\x=1,5\\\\\\Otvet \ : \ A \ \ \Big(1 \ ; \ 2\Big)$