Question

3.14. При каком значении аргумента значение функции равно 4
помогите плизз нужен ответ с решением.​

Answer 1

$\displaystyle\bf\\f(x)=4\\\\1)\\\\f(x)=\frac{6}{x-2} \\\\\\\frac{6}{x-2} =4\\\\\\4\cdot(x-2)=6\\\\4x-8=6\\\\4x=14\\\\\boxed{x=3,5}\\\\\\2)\\\\f(x)=\frac{x+1}{x-3} \\\\\\\frac{x+1}{x-3} =4\\\\\\4\cdot(x-3)=x+1\\\\4x-12=x+1\\\\4x-x=1+12\\\\3x=13\\\\\\\boxed{x=4\frac{1}{3}}$

$\displaystyle\bf\\3)\\\\f(x)=\frac{3}{x} +3\\\\\\\frac{3}{x} +3=4\\\\\\\frac{3}{x} =1\\\\\\\boxed{x=3}\\\\\\4)\\\\f(x)=\frac{x}{x-2} +5\\\\\\\frac{x}{x-2}+5=4\\\\\\\frac{x}{x-2} =-1\\\\\\-1\cdot(x-2)=x\\\\-x+2=x\\\\-x-x=-2\\\\-2x=-2\\\\\boxed{x=1}$