Question

выполните деление:

y²-10y+25
-------------- : (5-y)²
2y-10​

Answer 1

$\dfrac{y^2-10y+25}{2y-10}:(5-y)^2=\dfrac{(y-5)^2}{2(y-5)}:(5-y)^2=\\=\dfrac{y-5}{2}:(y-5)^2=\dfrac{y-5}{2(y-5)^2}=\dfrac{1}{2(y-5)}.$