Question

(2x+3) (3y-1)=2x×3y-2x+3y-3=6xy-2x+÷×3y-3=6xy-2x+9y-3 ВІРНО??​

Answer 1

$\displaystyle\bf\\\Big(2x+3\Big)\Big(3y-1\Big)=2x\cdot 3y-2x\cdot 1+3\cdot 3y-3\cdot 1=6xy-2x+9y-3$

Answer 2

Объяснение:

(2х+3)(3у-1)=2х×3у+2х×(-1)+3×3у+3×(-1)=

=6ху-2х+9у-3