Question

Алгебра.

Решить задания.

Answer 1

$\displaystyle\bf\\1)\\\\\Big(2x+3y\Big)^{4} \cdot\Big(2x+3y\Big)^{5} =\Big(2x+3y\Big)^{4+5} =\boxed{\Big(2x+3y\Big)^{9}} \\\\\\2)\\\\n^{2} \cdot n^{3} \cdot n=n^{2+3+1} =\boxed{n^{6}} \\\\\\3)\\\\\Big(x^{3} \Big)^{4} :\Big(x^{2} \Big)^{3} =x^{3\cdot 4} :x^{2\cdot 3} =x^{12}:x^{6} =x^{12-6} =\boxed{x^{6} }$