Question

решите уравнение 6*(b-3)=10-2*(b+2)_____________________________________


83+5*(y-3)=3*(8y-9)

Answer 1

6*(b-3)=10-2*(b+2)
6b-18=10-2b-4
6b+2b=10-4+18
8b=24
b=24/8
b=3
6*(3-3)=10-2*(3+2)
0=0

83+5*(y-3)=3*(8y-9)
83+5y-15=24y-27
83-15+27=24y-5y
95=19y
y=95/19
y=5
83+5(5-3)=3(8*5-9)
83+10=3*31
93=93