Question

Нужно решение ооооочень срочно, помогите пожалуйста

Answer 1

Ответ и Пошаговое объяснение:

$\displaystyle \tt \left (\begin{array}{ccccc} 1&4&5&6&-4 \\-2&3&-1&5&-1\\3&5&2&-9&2\\2&1&-4&5&2\\-3&3&4&1&-1 \end{array}\right ) \cdot \left (\begin{array}{ccccc} 6&-2&3&2&4 \\-3&8&2&-9&-3 \\-1&9&-3&5&3\\4&2&8&-3&0\\-1&8&0&7&6 \end{array}\right ) =\\\\= \left (\begin{array}{ccccc} c_{11}&c_{12}&c_{13}&c_{14}&c_{15} \\c_{21}&c_{22}&c_{23}&c_{24}&c_{25} \\c_{31}&c_{32}&c_{33}&c_{34}&c_{35} \\c_{41}&c_{42}&c_{43}&c_{44}&c_{45} \\c_{51}&c_{52}&c_{53}&c_{54}&c_{55} \end{array}\right )$

c₁₁=1·6+4·(-3)+5·(-1)+6·4+(-4)·(-1)=6-12-5+24+4 = 17

c₁₂=1·(-2)+4·8+5·9+6·2+(-4)·8=-2+32+45+12-32 = 55

c₁₃=1·3+4·2+5·(-3)+6·8+(-4)·0=3+8-15+48+0 = 44

c₁₄=1·2+4·(-9)+5·5+6·(-3)+(-4)·7=2-36+25-18-28 = -55

c₁₅=1·4+4·(-3)+5·2+6·0+(-4)·6=4-12+10+0-24 = -22

c₂₁=(-2)·6+3·(-3)+(-1)·(-1)+5·4+(-1)·(-1)=-12-9+1+20+1 = 1

c₂₂=(-2)·(-2)+3·8+(-1)·9+5·2+(-1)·8=4+24-9+10-8 = 21

c₂₃=(-2)·3+3·2+(-1)·(-3)+5·8+(-1)·0=-6+6+3+40+0 = 43

c₂₄=(-2)·2+3·(-9)+(-1)·5+5·(-3)+(-1)·7=-4-27-5-15-7 = -58

c₂₅=(-2)·4+3·(-3)+(-1)·2+5·0+(-1)·6=-8-9-2+0-6 = -25

c₃₁=3·6+5·(-3)+2·(-1)+(-9)·4+2·(-1)=18-15-2-36-2 = -37

c₃₂=3·(-2)+5·8+2·9+(-9)·2+2·8=-6+40+18-18+16 = 50

c₃₃=3·3+5·2+2·(-3)+(-9)·8+2·0=9+10-6-72+0 = -59

c₃₄=3·2+5·(-9)+2·5+(-9)·(-3)+2·7=6-45+10+27+14 = 12

c₃₅=3·4+5·(-3)+2·2+(-9)·0+2·6=12-15+4+0+12 = 13

c₄₁=2·6+1·(-3)+(-4)·(-1)+5·4+2·(-1)=12-3+4+20-2 = 31

c₄₂=2·(-2)+1·8+(-4)·9+5·2+2·8=-4+8-36+10+16 = -6

c₄₃=2·3+1·2+(-4)·(-3)+5·8+2·0=6+2+12+40+0 = 60

c₄₄=2·2+1·(-9)+(-4)·5+5·(-3)+2·7=4-9-20-15+14 = -26

c₄₅=2·4+1·(-3)+(-4)·2+5·0+2·6=8-3-8+0+12 = 9

c₅₁=(-3)·6+3·(-3)+4·(-1)+1·4+(-1)·(-1)=-18-9-4+4+1 = -26

c₅₂=(-3)·(-2)+3·8+4·9+1·2+(-1)·8=6+24+36+2-8 = 60

c₅₃=(-3)·3+3·2+4·(-3)+1·8+(-1)·0=-9+6-12+8+0 = -7

c₅₄=(-3)·2+3·(-9)+4·5+1·(-3)+(-1)·7=-6-27+20-3-7 = -23

c₅₅=(-3)·4+3·(-3)+4·2+1·0+(-1)·6=-12-9+8+0-6 = -19

#SPJ1