Question

(1/3) ^(x^2) >(1/3) ^(3x+4)

Answer 1

Ответ:

решение смотри на фотографии

Answer 2

$\displaystyle\bf\\\Big(\frac{1}{3} \Big)^{x^{2} } > \Big(\frac{1}{3} \Big)^{3x+4} \\\\\\0 < \frac{1}{3} < 1 \ \ \ \Rightarrow \ \ \ x^{2} < 3x+4\\\\\\x^{2} -3x-4 < 0\\\\(x+1)(x-4) < 0\\\\\\+ + + + + (-1) - - - - - (4) + + + + +$

                        \\\\\\\\\\\\\\\\

$\displaystyle\bf\\Otvet \ : \ x\in\Big(-1 \ : \ 4\Big)$