Предмет: Математика, автор: Mr1rat

Знайти площу повної поверхні прямої призми, в основі якої лежить ромб з довжиною сторони 5 см і гострим кутом 30', а висота цієї призми дорівнює 10 см.

Ответы

Автор ответа: nazikmuz

Відповідь:

S = 225 (см^2)

Покрокове пояснення:

$S$ осн = $5^2 * sin30^{0} = 25*\frac{1}{2} = 12.5$ (см^2)

$S$ пов = $2S$ осн $+ S$ біч = $2 * 12.5 + P * H = 25 + 4 * 5 * 10 = 225$ (см^2)

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Знайти площу повної поверхні прямої призми, в основі якої лежить ромб з довжиною сторони 5 см і гострим кутом 30', а висота цієї призми дорівнює 10 см.​

Ответы

Знайти площу повної поверхні прямої призми, в основі якої лежить ромб з довжиною сторони 5 см і гострим кутом 30', а висота цієї призми дорівнює 10 см.