Question

помогите пожалуйста решить​ 3 и 6

Answer 1

3. Ответ: 5

$\frac{( {5}^{3} ){}^{5} \times {3}^{16} }{9 \times 225 {}^{7} } = \frac{ {5}^{15} \times {3}^{16} }{ {3}^{2} \times 25 {}^{7} \times 9 {}^{7} } = \frac{ {5}^{15} \times {3}^{16} }{ {3}^{2} \times ({5}^{2}) {}^{7} \times ({3}^{2}) {}^{7} } = \frac{ {5}^{15} \times {3}^{16} }{ {3}^{2} \times {5}^{14} \times {3}^{14} } = \frac{ {5}^{15} \times {3}^{16} }{ {5}^{14} \times {3}^{16} } = 5$

6. Ответ: x1=3 ; x2=-2

$(x - 3)(6x + 5) = (x - 3)(2x - 3) \\ {6x}^{2} + 5x - 18x - 15 = {2x}^{2} - 3x - 6x + 9 \\ {6x}^{2} - 13x - 15 = {2x}^{2} - 9x + 9 \\ {6x}^{2} - {2x}^{2} - 13x + 9x - 15 - 9 = 0 \\ {4x}^{2} - 4x - 24 = 0 \\ {x}^{2} - x - 6 = 0$

Через теорема Виета:

x1+x2=-p

x1•x2=q

x1+x2=-(-1)=1

x1•x2=-6

x1=3

x2=-2