Question

$4tg^{2} x$-tgx-3=0

Answer 1

4tg²x-tgx-3=0

Замена: t=tgx

4t²-t-3=0

D=b²-4ac=1-4*4*(-3)=49.    √49=7

x1=(1+7)/8=8/8=1.

x2=(1-7)/8=-6/8=-3/4.

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          tgα=a

    α=arctg(a)+pi*k

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tgx=1 => x=pi*k+pi/4.

tg=-3/4 => x=pi*k-arctg(3/4).