Question

x^2+7x/4+x=2x-6/4+x
Помогите пожалуйста

Answer 1

Ответ:

$\frac{ {x}^{2} + 7x }{4 + x} = \frac{2x - 6}{4 + x} \\ {x}^{2} + 7x = 2x - 6 \\ {x}^{2} + 7x - 2x + 6 = 0 \\ {x}^{2} + 5x + 6 = 0 \\ {x}^{2} + 2x + 3x + 6 = 0 \\ x(x + 2) + 3(x + 2) = 0 \\ (x + 2)(x + 3) = 0 \\ x + 2 = 0 \\ x = - 2 \\ \\ x + 3 = 0 \\ x = - 3 \\ \\ \\ \\ - 2 \: \: - 3$