Question

Даю 30 балів,поможіть​

Answer 1

1)

$\frac{1}{3}\sqrt{27} =\frac{1}{3}\sqrt{3*9}=\frac{1}{3}*3\sqrt{3} =\sqrt{3}$

$\sqrt{2a^7}=a^3\sqrt{2a}$

2)

$5\sqrt{a}=\sqrt{25a} \\3k\sqrt{\frac{1}{k^2} } =k\sqrt{\frac{9}{k^2} }$

3)

$\frac{4}{\sqrt{xy} } =\frac{4*\sqrt{xy} }{\sqrt{xy}*\sqrt{xy} } =\frac{4\sqrt{xy} }{xy}$

$\frac{3}{\sqrt{5} +\sqrt{2} }=\frac{3(\sqrt{5}-\sqrt{2} )}{(\sqrt{5} +\sqrt{2})(\sqrt{5} -\sqrt{2} ) } = \frac{3(\sqrt{5} -\sqrt{2} )}{5-2} =\sqrt{5} -\sqrt{2}$

4)

$y=\sqrt{x} \\y=\sqrt{9}\\ y=3$