Question

9+6у+4у^2/2y-1*4y-1/27-8y^3=2у+1/3-2y
довести тожденство

Answer 1

Ответ:

ø

Объяснение:

(9+6y+4y²)/(2y-1)*(4y-1)/(27-8y³)=2y+⅓-2y;

(4y²+6y+9)/(2y-1)*(4y-1)/(27-8y³)=⅓;

(4y²+6y+9)(4y-1)/(2y-1)(27-8y³)=⅓;

(4y²+6y+9)(4y-1)/(2y-1)(3-2y)(9+6y+4y²)=⅓

(4y-1)/(2y-1)(3-2y)=⅓;

(4y-1)/(6y-4y²-3+2y)=⅓;

(4y-1)/(-4y²+8y-3)=⅓;

(4y-1)/(y+3/2)(y+½)=⅓;

(4y-1)/-4(y-1,5)(y-0,5)=1/3;

3(4y-1)= -4(y-1,5)(y-0,5)

12y-3= -4y²+8y-3;

12y= -4y²+8y

тождество не всегда верно.